Math, asked by dcvikas2007, 1 day ago

The triangular side walls of a Fly over have been used for advertisement The site of the walls are 122 m, 22 ,and 120 m. The advertisement yields on hearing of ₹.5000 per Square metre Per year a company here on of its
Here a=122m, b=120m, c=22
:s=122+120+22/2
=204/2
=132

Answers

Answered by aksharavijairamyasre
0

Answer:Correct option is

A   .Rs.16,500,000  PLEASE MARK ME THE BRAINLEIST

Step-by-step explanation:Refer figure,

In △ABC

a=122m,b=22m,c=120m

s=  

2

a+b+c

=  

2

122+22+120

 

=132m

ar△ABC=  

s(s−a)(s−b)(s−c)

=  

132(132−122)(132−23)(132−120)

 

=  

132×10×110×12

=  

132×10×11×10×12

=  

(132)  

2

×(10)  

2

 

 

=132×10=1320 m  

2

 

Rent of 1 m  

2

 per year = Rs. 5000

Rent of 1 m  

2

 per month = Rs.  

12

5000

 

Rent of 1 m  

2

 for 3 months=Rs.  

12

3×5000

 

Rent of 1320 m  

2

 for 3 months=Rs. (  

12

3×5000×1320

)

= Rs.16,500,000

Answered by r27272278
0

ans is 16,500,000

hope it helpful to you

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