Question

The triangular side walls of a fly over have been used for advertisements. The sides of the walls are 122 m,120m ,22m .The advertisements yield an earning of rupee 5000 per metre square per year . A company hired one
of its walls for 3 months .How much rent did it play

Answer 1

Answer:

For 3 months the company would pay 1,486,200 rupees as the rent.

Step-by-step explanation:

triangle area = $\sqrt[2]{p(p-a)(p-b)(p-c)}$

where, p = $\frac{a+b+c}{2}$

now, p = $\frac{122 + 120 + 22 }{2}$

so, p = 264 ÷ 2

so, p = 131 m.

now area = $\sqrt[2]{131 (131 - 122) (131 - 120) (131 - 22)}$

so, area = $\sqrt[2]{131 (9) (11) (109)}$

so, area = $\sqrt[2]{1,413,621}$

so, area = 1188.96 m²

now, per year per m², rupees earned are 5000,

so, per year, per 1188.96 m², rupees earned would be = 5000 x 1188.96 = 5,944,800 rupees.

now, per 12 months, rupees earned are 5,944,800,

so, per 3 months, rupees earned would be 5,944,800 ÷ 4 = 1,486,200 rupees.