Question

the triangular side walls of a flyover have been used for advertisement the sides of the walls are 122m,22mand 120 the advertisementstime and Shield and earning of rupees 5000 per metre square per year company hire one of its walls for 3 months how much rent it bae ​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Its rent would be Rs. 1650000.

Step-by-step explanation:

Since we have given that

Dimensions of triangle are 122 m, 22 m, 120 m

So, Area of triangle would be

$\sqrt{s(s-a)(s-b)(s-c)}$

Here, $s$ is the half perimeter of dimensions $a,b,c$.

So, $s=\dfrac{a+b+c}{2}=\dfrac{122+22+120}{2}=\dfrac{264}{2}=132\ m$

So, Area of triangle would be

$\sqrt{132(132-122)(132-22)(132-120)}\\\\=\sqrt{132\times 10\times 110\times 12}\\\\=1320$

Cost per square meter = Rs. 5000

It is hire for 3 months.

So, total cost would be

$1320\times 5000\times \dfrac{3}{12}\\\\=1650000$

Hence, its rent would be Rs. 1650000.

# learn more:

The triangular side walls of a flyover have been used for advertisement. The sides of the walls are 122m, 22m, and 120m. The advertisement yield an earning of Rs5000 per m²per year. A company hired one of its walls for 3 months. How much rent did it pay ​

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