Question

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield an earning of rs 2000 per m2 a year. A company hired one of its walls for 6 months. How much rent did it pay?

Answer 1

Step-by-step explanation:

in this triangle

let, a=13m

b=14m

c=15m

as ,

S= a+b+c /2

S= 13+15+14/2

S= 42/2

S=21

(S-a) = 21-13=8m

(S-b)=21-14= 7m

( S-c)= 21-15 = 6m

ar(ABC) by heron's formula

$\sqrt{s - a \times s - b \times s - c \times s}$

.

$\sqrt{21 \times 8 \times 7 \times 6}$

$\sqrt{3 \times 7 \times 2 \times 2 \times 2 \times 7 \times 3 \times 2}$

$3 \times 7 \times 2 \times 2$

84m square

total earning from the triangle of Rs 2000 per m square = 84*2000

= Rs 168000

earning of 12 months =Rs 168000

earning of 1 month = Rs 168000/12

earning of 6 months = Rs. (168000/12) * 6

= Rs 84000

Hope It has helped you