Question

The triangular side walls of a flyover have been used for advertisements. The sides of
the walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertisements yield a
earning of 5000 per m² per year. A company hired one of its walls for 3 months. How
much rent did it pay?​

Answer 1

₹16,50,000

Step-by-step explanation:

total area of triangular wall =

√{s(s-a)(s-b)(s-c)} where s = (a+b+c)/2

√{132×10×110×12}

= √1742400

= 1320 m²

earning in 3 month per m² = 5000/4=1250

rent paid 1320×1250 = ₹16,50,000

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