Question

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see Fig.). The advertisements yield as earning of Rs. 5000 per m 2 per year. A company hired one of its walls for 3 months. How much rent did it pay ?​

Answer 1

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Answers

The sides of the triangle are: а — 122m, b

120m and c = 22m

The semi perimeter, s will be

a +b+c 122 + 120 + 22

S = 2 2

Therefore, the area of the triangular side wall

will be calculated by the Heron's Formula,

A= s(s – a)(s – b)(s – e) S

√132(132 122)(132 120)(132 22)

1321012110 m²

(12 x 11101211 × 10) m = 13 Given the rent for 1 year (i.e., 12 months) per meter square is Rs. 5000.

Rent for 3 months per meter square will be:

Rs. 5000 x 3

12

Therefore, for 3 months for 1320 m2 :

Rs. 5000 x 3/12 x 1320 = Rs. 16,50,000

HENCE ANSWER IS:- 16,50,000Rs.

Answer 2

Answer:

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