the triangular side walls of a flyover have been used for advertisements the side of the walls are 12222 and 120 the advertisement seals and earning of rupees 5000 per metre square per year accompany your one of its walls for 3 months how much rent it pay
Answers
Answer:
Refer figure,
In △ABC
a=122m,b=22m,c=120m
s=
2
a+b+c
=
2
122+22+120
=132m
ar△ABC=
s(s−a)(s−b)(s−c)
=
132(132−122)(132−23)(132−120)
=
132×10×110×12
=
132×10×11×10×12
=
(132)
2
×(10)
2
=132×10=1320 m
2
Rent of 1 m
2
per year = Rs. 5000
Rent of 1 m
2
per month = Rs.
12
5000
Rent of 1 m
2
for 3 months=Rs.
12
3×5000
Rent of 1320 m
2
for 3 months=Rs. (
12
3×5000×1320
)
= Rs.16,500,000
solution
Answer:
PLSS MARK IT BRAINLEIST
Step-by-step explanation:
Refer figure,
In △ABC
a=122m,b=22m,c=120m
s= 2
a+b+c =2
122+22+120=132m
ar△ABC= root s(s−a)(s−b)(s−c)
= root 132(132−122)(132−23)(132−120)
= root 132×10×110×12
=root 132×10×11×10×12
=root (132)2×(10)2
=132×10=1320 m2
Rent of 1 m2 per year = Rs. 5000
Rent of 1 m2 per month = Rs. 125000
Rent of 1 m2 for 3 months=Rs.123×5000
Rent of 1320 m2
for 3 months=Rs. (123×5000×1320 )
= Rs.16,500,000
