the triangular side walls of a flyover have been used for advertisements the side of the walls are 122,22 and 120 the advertisement seals and earning of rupees 5000 per metre square per year a company heird
one of its walls for 3 months how much rent it pay
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The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see Fig.). The advertisements yield as earning of Rs. 5000 per m
2
per year. A company hired one of its walls for 3 months. How much rent did it pay ?
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ANSWER
Refer figure,
In △ABC
a=122m,b=22m,c=120m
s=
2
a+b+c
=
2
122+22+120
=132m
ar△ABC=
s(s−a)(s−b)(s−c)
=
132(132−122)(132−23)(132−120)
=
132×10×110×12
=
132×10×11×10×12
=
(132)
2
×(10)
2
=132×10=1320 m
2
Rent of 1 m
2
per year = Rs. 5000
Rent of 1 m
2
per month = Rs.
12
5000
Rent of 1 m
2
for 3 months=Rs.
12
3×5000
Rent of 1320 m
2
for 3 months=Rs. (
12
3×5000×1320
)
= Rs.16,500,000
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