Question

the triangular side walls of a flyover have been used for advertisement .the side of the wall are 122m 20 m and 120m metre the advertisement real and earning of rupees 5000 beer company hired the one of its wall for 3 months how much run did it pay? ​

Answer 1

Answer:

In △ABC

a=122m,b=22m,c=120m

s= a+b+c /2

s = 122+22+120 /2

s = 132m

ar△ABC= √s(s−a)(s−b)(s−c)

= √132(132−122)(132−23)(132−120)

= √132×10×110×12

= 132×10

= (132) ×(10)

=1320 m

Rent of 1 m

per year = Rs. 5000

Rent of 1 m

per month = Rs.5000

Rent of 1 m

2

for 3 months=Rs.

12

3×5000

Rent of 1320 m

2

for 3 months=Rs. (

12

3×5000×1320

)

= Rs.16,500,000

plz also mark it as brainliest