Question

The triangular side walls of a flyover have been used for advertisements. The sides of
the walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertisements yield an
earning of 3 5000 per m’ per year. A company hired one of its walls for 3 months. How
much rent did it pay?​

Answer 1

Answer:

Reffer the attachment for your answer mate

Answer 2

Answer⤵

The sides of the triangle ABC are 122 m, 22 m and 120 m respectively.

The sides of the triangle ABC are 122 m, 22 m and 120 m respectively.Now, the perimeter will be (122+22+120) = 264 m

The sides of the triangle ABC are 122 m, 22 m and 120 m respectively.Now, the perimeter will be (122+22+120) = 264 mAlso, the semi perimeter (s) = 264/2 = 132 m

The sides of the triangle ABC are 122 m, 22 m and 120 m respectively.Now, the perimeter will be (122+22+120) = 264 mAlso, the semi perimeter (s) = 264/2 = 132 mUsing Heron’s formula,

The sides of the triangle ABC are 122 m, 22 m and 120 m respectively.Now, the perimeter will be (122+22+120) = 264 mAlso, the semi perimeter (s) = 264/2 = 132 mUsing Heron’s formula,Area of the triangle =(in the attachment)

=1320 m2

=1320 m2We know that the rent of advertising per year = ₹ 5000 per m2

=1320 m2We know that the rent of advertising per year = ₹ 5000 per m2∴ The rent of one wall for 3 months = Rs. (1320×5000×3)/12 = Rs. 1650000

$\huge \red {\colorbox {black}{@vanunagar13}}$