Question

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see Fig.). The advertisements yield as earning of Rs. 5000 per m^2
per year. A company hired one of its walls for 3 months. How much rent did it pay ?

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Answer 1

Answer:

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Answer 2

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Tʜᴇ sɪᴅᴇs ᴏғ ᴛʜᴇ ᴛʀɪᴀɴɢᴜʟᴀʀ ᴡᴀʟʟ ᴀʀᴇ =

$a = 122m$

$b = 22m$

$c = 120m$

$s = \frac{a + b + c}{2}$

$\frac{122 + 22 + 120}{2}$

$\frac{264}{2}$

$= 132$

Aʀᴇᴀ ᴏғ ᴛʀɪᴀɴɢᴜʟᴀʀ ᴡᴀʟʟ =

$\sqrt{ s(s - a)(s - b)(s - c)}$

$\sqrt{132(132 - 122)(132 - 22)(132 - 120)}$

$\sqrt{ = 132 \times 10 \times 110 \times 12}$

$= 10 \times 11 \times 12$

$= 1320 {m}^{2}$

Cᴏsᴛ ᴏғ ʜɪʀɪɴɢ ᴛʜᴇ ᴡᴀʟʟs ғᴏʀ ᴛʜʀᴇᴇ ᴍᴏɴᴛʜs =

$area \times rate \times time$

$1320 = 5000 \times \frac{1}{4}$

$= 330 \times 5000$

$= rs \: 1650000$

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