Question

the triangular side walls of a flyover have been used for advertisements. the sides of the walls are 122m, 22m and 120m. the advertisements yield an earning of rs.5000msq. a company hired one of its walls for 3 months. how much rent did it pay??​

Answer 1

$\huge \fbox \blue{Answer}$

Refer figure,

In △ABC

a=122m,b=22m,c=120m

s=

2

a+b+c

=

2

122+22+120

=132m

ar△ABC=

s(s−a)(s−b)(s−c)

=

132(132−122)(132−23)(132−120)

=

132×10×110×12

=

132×10×11×10×12

=

(132)

2

×(10)

2

=132×10=1320 m

2

Rent of 1 m

2

per year = Rs. 5000

Rent of 1 m

2

per month = Rs.

12

5000

Rent of 1 m

2

for 3 months=Rs.

12

3×5000

Rent of 1320 m

2

for 3 months=Rs. (

12

3×5000×1320

)

= Rs.16,500,00

Answer 2

Here is the answer mate〰