Math, asked by boythebest24, 1 year ago

the triangular side walls of a flyover have been used for advertisement the side of the walls are 122 M 22 M and 120 M the advertisement yield an earning of 5000 per metre sq. per year a company had one of it wall for 3 month how much rent did it pay

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Answers

Answered by Anonymous
5

Answer:

⇒ Rs. 3300000

Step-by-step explanation:

The length of the side of the boys are 122 m, 22 m and 120 m.

We have,

⇒ 122² = 120² + 22²

So, walls are in the form of right ∆s.

Therefore,

Area of two walls = 2 × (1/2 × Base × Height)

⇒ Area of the two walls = 2 × ( 1/2 × 120 × 22 )

⇒ 2640 m²

We have,

Yearly rent = Rs. 5000 per m²

Therefore,

Monthly rent = Rs. ( 5000/12) per m²

Hence,

Rent paid by the company for 3 months:

⇒ Rs. ( 5000/12 × 3 × 2640 )

⇒ Rs. 3300000

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Answered by Anonymous
1

Answer:

Reffer the attachment for your answer mate

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