Math, asked by anantgupta5com, 3 months ago

The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 13 m, 14 m and 15 m. The advertisements yield an earning of Rs.2000 per m2 a year.

The area of triangular side wall is
(i) 84 m2
(ii) 42 m2
(iii) 44 m2
(iv) 86 m2

Answers

Answered by prabhas24480
1

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 \large \tt  \red{✦Answer✦}

S= 13+14+15/2 =42/2 =21

area of triangular region=. √21×8×7×6

=84m2

cost of advertisement perm2 a year =2000

cost advertisement of 6month. = 2000×6/12

cost of advertisement 84m2for 6month=2000×6×84/12=84000

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