Question

the triangular side walls of a flyover have been used for advertisement the sides of the world are 13, 14 and 15 meter. the advertisement year old and earning of rupees 2000 per metre square a year .a company hired one of its wall for 6 months. how much rent did it pay ?​

Answer 1

Answer:

$first \: we \: need \: to \: find \: the \: area \\ of \: the \: rented \: walls \\ \\ by \: herons \: formula \\ = \sqrt{s(s - a)(s - b)(s - c)} \\ = \sqrt{21(21 - 13)(21 - 14)(21 - 15) } \\ = \sqrt{21 \times 8 \times 7 \times 6} \\ = \sqrt{7056} \\ = 84 {m}^{2} \\ cost \: for \: 1 {m}^{2} = 2000 \\ cost \: for \: 84{m}^{2} = 84 \times 2000 \\ = 168000rs. \\ \\ cost \: for \: 1 \: year \: = 168000rs. \\ cost \: for \: 12 \: \\ = months \: = 168000rs. \\ cost \: for \: 1 \: month = \frac{168000}{12} \\ cost \: for \: 6 \: months \: = \frac{168000}{12} \times 6 \\ = 84000rs.$

therefore the answer is 84,000 rupees

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Answer 2

Answer:

the answer is₹84,000

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