The triangular side walls of a flyover have beon used for advertisements. They How
the walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertisements yield an
earning of 3 5000 per m² per year. A company hired one of its walls for 3 months.How
much rent did it pay?
Answers
Answer:
The sides of the triangle (i.e., a, b, c) are of 122 m, 22 m, and 120 m respectively. Therefore, the company had to pay Rs 1650000.
Step-by-step explanation:
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Answer:
Step-by-step explanation:
Let the sides of the triangle are a=122 m, b=22 m & c= 120 m.
Semi Perimeter of the ∆,s = (a+b+c) /2
s=(122 + 22 + 120) / 2
s= 264/2= 132m
Using heron’s formula,
Area of the wall = √s (s-a) (s-b) (s-c)
= √132(132 – 122) (132 – 22) (132 – 120)
= √132 × 10 × 110 × 12
=√11×12×10×11×10×12
=√11×11×12×12×10×10
= 11×12×10
= 1320m²
Given, earning on 1m² per year= ₹5000
Earning on 1320 m² per year=1320×5000= ₹6600000
Now, earning in 1320 m² in 12 months= ₹6600000
earning in 3 months = ₹ 6600000 ×3/12 = ₹ 1650000
Hence, the rent paid by the company for 3 months is ₹ 1650000.
ANSWERED BY GAUTHMATH