Question

The triangular side walls of a flyover is used for advertisement. The sides of walls are 112m, 32m and 120m. The advertisement yields an earning of ₹ 6000 per metre square per year. A company fixed of its wall for 4 months. How much rent did it pay ?

Answer 1

Answer:

10752000

Step-by-step explanation:

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Answer 2

Given:-

• The triangular side wall sides are 112 m , 32 m and 120 m.

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To find:-

• How much rent does it pay for 4 months.

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$\huge \tt \: ☃ \: SolutioN$

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By using formula -

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Heron's formula that is

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$\sqrt{s(s - a)(s - b)(s - c)}$

In which,

• s is semi-perimeter.
• a , b and c are side of triangle.

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✶ Semi- perimeter = $\frac{perimeter \: of \: triangle}{2}$

So,

Perimeter of triangle = 112 + 32 + 120

= 264 m

Semi-perimeter = $\frac{</strong><strong>2</strong><strong>6</strong><strong>4</strong><strong>}{2}$

= 132 m

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Area of wall

→$\sqrt{s(s - a)(s - b)(s - c)}$

→$\sqrt{132(132 - 120)(132 - 32)(132 - 112)}$

→$\sqrt{132×12×100×20}$

→$\sqrt{3168000}$

→1779.88 m²

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If ₹ 6000 = 1 m² per year

→ 1779.88 =₹ 1779.88 × 6000

→ ₹10679280

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12 months = ₹10679280

→ 4 months = $\frac{</strong><strong>1</strong><strong>0</strong><strong>6</strong><strong>7</strong><strong>9</strong><strong>2</strong><strong>8</strong><strong>0</strong><strong>×</strong><strong>4</strong><strong>}{</strong><strong>1</strong><strong>2</strong><strong>}$

→₹ 3559760

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Therefore, It pay for 4 months is ₹ 3559760.