Question

The triangular wall of a flyover have been used for advertisment.the side of wall are 22 m, 122m and 120m. The advertisement yield an earning of rain Rs.5000 per meter square per year. A company hired one of its wall for month. How much rent did it pay?

Answer 1

The rent paid by the company for 3 months is Rs. 1650000

Step-by-step explanation:

Given:

The sides : 22 m, 122m and 120m.

The advertisement yield an earning of rain Rs.5000 per meter square per year.

To Find :

The rent paid by the company.

Solution :

Let's Consider the sides of triangle as,

• a - 122m
• b - 22 m
• c - 120 m.

Let's find the Semi Perimeter of the triangle.

$\bigstar\;\boxed{\bf \dfrac{S = (a+b+c)}{2}}}\\ \\ \\\implies \sf \dfrac{s=(122 + 22 + 120)}{2}\\ \\ \\\implies \sf s= \dfrac{264}{2}\\ \\ \\\implies \bf 132m$

We know the Heron's Formula,

So,

$\bigstar\;\boxed{\bf Area\; of\; the \;wall = \sf \sqrt{s (s-a) (s-b) (s-c)}}}\\ \\ \\\implies \sf \sqrt{132(132 -122) (132 -22) (132 -120)}\\ \\ \\\implies \sf \sqrt{132 \times 10 \times 110 \times 12}\\ \\ \\\implies \sf \sqrt{11 \times 12 \times 10 \times 11 \times 10 \times 12}\\ \\ \\\implies \sf \sqrt{11 \times 11 \times 12 \times 12 \times 10 \times 10}\\ \\ \\\implies \sf 11 \times 12 \times 10\\ \\ \\ \implies \bf 1320m^2$

$\rule{300}{1.5}$

Now,

Given :

The earning on 1m² per year = Rs. 5000

Earning on 1320 m² per year :

⇒ 1320 × 5000

⇒ Rs. 6600000

Now, earning in 1320 m² in 12 months :

⇒ Rs. 6600000

Earning in 3 months:  Rs. 6600000 × $\sf \dfrac{3}{12}$ = Rs. 1650000

Hence,

The rent paid by the company for 3 months is Rs. 1650000.