Question

the triangular walls of a flyover have been used for ad. the side are 122m, 22m, 120m. the ads yield an amount of ₹5000/m²per year. a company hired one of its walls for 3 months. how much rent did it pay?​

Answer 1

Answer:

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Step-by-step explanation:

Answer

5.0/5

3

Answer:

Rs 16,500,000

Step-by-step explanation:

Refer figure,

In △ABC

a=122m,b=22m,c=120m

s=  

2

a+b+c

​  

=  

2

122+22+120

​  

 

=132m

ar△ABC=  

s(s−a)(s−b)(s−c)

​  

=  

132(132−122)(132−23)(132−120)

​  

 

=  

132×10×110×12

​  

=  

132×10×11×10×12

​  

=  

(132)  

2

×(10)  

2

 

​  

 

=132×10=1320 m  

2

 

Rent of 1 m  

2

per year = Rs. 5000

Rent of 1 m  

2

per month = Rs.  

12

5000

​  

 

Rent of 1 m  

2

for 3 months=Rs.  

12

3×5000

​  

 

Rent of 1320 m  

2

for 3 months=Rs. (  

12

3×5000×1320

​  

)

= Rs.16,500,000