Question

the trigonometric equation given by 
sin(x) + sin(x/2) = 0 for 0 ≤ x ≤ 2 pi​

Answer 1

Explanation:

1 + cos(x) + cos(2x) ] / [ sin(x) + sin(2x) ]

= [ 1 + cos(x) + 2 cos2(x) - 1 ] / [ sin(x) + 2 sin(x) cos(x) ]

= [ cos(x) + 2 cos2(x) ] / [ sin(x) + 2 sin(x) cos(x) ]

= cos(x) [1 + 2 cos(x)] / [ sin(x)( 1 + 2 cos(x) ) ]

= cot(x)

Answer 2

Trigonometry Solve for x sin(x)+sin(x/2)

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