Question

the trinomial p(x)= x^3-x has three real zeroes
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Answer 1

Answer:

Given P(x)=x

3

−x

To find the zeros of P(x), let P(x)=0

⟹x

3

−x=0

⟹x(x

2

−1)=0

⟹x(x−1)(x+1)=0

⟹x=0 and x−1=0 and x+1=0

⟹x=0,1,−1 are the zeros of P(x)

Thus, the number of zeros of P(x) is 3.

Hence, the answer is 3.

Answer 2

Answer:

Step-by-step explanation:

Yes because the highest power of x is 3 hence the number of zeroes are 3

I hope my answer helps you