Question

The triple points of neon and carbon dioxide are 24.57 K and 216.55 K respectively. Express these temperatures on the Celsius and Fahrenheit scales.

Answer 1

concept :-
K = C + 273.15
and C/5 = ( F - 32)/9
Where, K is Kelvin , C is Calcius and F is Fahrenheit.

For 24.57 K
In calcius ,
C = 24.57 - 273.15
C = -248.58° C

In Fahrenheit ,
-248.58/5 = ( F - 32)/9
F = -248.58 × 9/5 + 32
= -414.44°F

For 216.55 K,
in Celsius ,
C = 216.55 - 273.15
= -56.6°C

In Fahrenheit,
-56.6/5 = ( F - 32)/9
F = -56.6×9/5 + 32
= -69.88°F

Answer 2

Explanation:

The Kelvin and Celsius's scales are related as:

$T_{C} = T_{K} - 273.15. . . . . (i)$

Celsius and Fahrenheit's scales are related as:

$T_{F} = \frac{9}{5} T_{C} + 32. . . . . (ii)$

For neon:

$T_{K} = 24.57 K$

$\therefore\:T_{C} = 24.57 - 273.15 = -248.58^{\circ}C$

$T_{F} = \frac{9}{5} T_{C} + 32$

$= \frac{9}{5} (-248.58)+32$

$= 415.44^{\circ}F$

For carbon dioxide:

$T_{K} = 216.55 K$

$\therefore\:T_{C} = 216.55 - 273.15 = -56.60^{\circ}C$

$T_{F} = \frac{9}{5} (T_{C})+32$

$\frac{9}{5} (-56.60) + 32$

$= -69.88^{\circ}C$