Question

The triple points of neon and carbon dioxide are 24.57 K and 216.55 K respectively. Express these temperatures on the Celsius and Fahrenheit scales.

Answer 1

we know the relation between Kelvin, Celsius and Farhenhiet is given by

$\frac{K-273.15}{100}=\frac{C-0}{100}=\frac{F-32}{180}$


Triple point of Neon , $T_{Ne}$ = 24.57K

now, (24.57-273.15)/100 = (C - 0)/100 = (F - 32)/180

or, C/100 = (-248.58)/100

or, C = -248.58°C

and (F - 32)/180 = (-248.58)/100

or, F - 32 = 180/100 × (-248.58)

or, F - 32 = -447.444

or, F = 32 - 447.444 = 415.444°F


again, For Carbon dioxide:
$T_k$= 216.55 K

∴ $T_c$ = $T_k$ – 273.15

⇒ $T_c$ = 216.55 – 273.15

⇒ $T_c$ = -56.6 °C

And $T_f$ = (9/5)$T_c$ + 32

⇒ $T_f$ = (9/5)(-56.6) + 32

⇒ $T_f$ = -101.88 + 32

⇒ $T_f$ = -69.88 °F


NOTE: The triple point of a substance is the temperature and pressure at which the three phases (gas, liquid, and solid) of that substance coexist in thermodynamic equilibrium.

Answer 2

Answer:

Explanation:

U can calculate it by the formula

(F-273.15)/100=C/100=(F-32)/180