The truck is moving at a velocity of 60m/s. When brakes are applied, it slows down to 54km/h in 0.25 minutes
a) what is the rate of accelerationof the truck?
b) how far it has traveled during that time?
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Answer:
Hey buddy....
Here's the answer.
Given: velocities,
V1 = 60m/s
V2=54km/h = 15m/s
time taken 't' = 0.25 min = 15 sec
Now,
a)Rate of Acceleration (a) = V2–V1/ t
= 15-60/15
= -3 m/s²
b) distance (d) = ?
Distance 'd' = (V1+V2)* t
= (60+15)*15
= 1125 m.
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