Math, asked by julikripdc96, 4 months ago

The true statement for the graph
of inequations 3.x + 2v s 6 and
6.r + 4y > 20 is :
(A) Both graphs are disjoint
(B) Both do not contain origin
(C)
Both contain point
(D) None of the above​

Answers

Answered by ritesh701646
0

The true statement for the graph

of inequations 3.x + 2v s 6 and

6.r + 4y > 20 is :

Ans A

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