The trunk of a tree cracks at a point 10 m above the ground. The tree falls and its top touches the ground at a distance of 24 m from the base of the tree. Find the actual height of the tree.
Pls give step by step explaination
Answers
Answered by
4
Answer:
36M
Step-by-step explanation:
Let a triangle be ABC
AB=10 M
AC =24M
BC^2=AC^2+AB^2
=100+576=
676
BC=26M
LENGTH OF THE BROKE TREE IS 26 M
TOTAL Height OF THE TREE IS (26+10)M
=36M
Answered by
0
Answer:
36M
Step-by-step explanation:
Let a triangle be ABC
AB=10 M
AC =24M
BC^2=AC^2+AB^2
=100+576=
676
BC=26M
THE LENGTH OF THE BROKEN TREE IS 26 M
The TOTAL Height OF THE TREE IS (26+10)m
=36m
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