Question

The truss work of a house can be done by 6 expects or trainees in 15 days owner want to be completed in 9 days and 7 expects and n trainees can complete work in 9 days find n

Answer 1

If 6 expects or trainees can do the work in 15 days and 7 expects and n trainees can complete work in 9 days then n is 3.

Step-by-step explanation:

It is given that,  

6 expects or trainees can do the work in 15 days  

i.e., 6 Expects = 6 Trainees = 15  days

So, 7 Expects = 7 Trainees

∴ 7 Expects + n Trainees = 7 Trainees + n Trainees = (7 + n) Trainees ← can work for 9 days

Now, applying the Man-Days Formula, we have

M₁ * D₁ = M₂ * D₂

⇒ 6 * 15 = (7+n) * 9

⇒ 7 + n = 2 * 5

⇒ n = 10 - 7  

⇒ n = 3

Thus, the value of n is 3.

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Answer 2

Given: The truss work of a house can be done by $6$ expects or trainees in $15$ days and owner want to be completed in $9$ days.

To Find: What is the value of $n$.

Step-by-step explanation:

Here,

Given the truss complete the work by $6$ expects or trainees in $15$ days.

$6$ expects$=6$ trainees

So,

$7$ expects and $n$ trainees that means $(7+n)$ expects or trainees.

Now,

Applying the Man-Days Formula,

        $M_{1}\times D_{1}=M_{2}\times D_{2}$

    ⇒$6\times 15=(7+n)\times 9$ Where, $M_{1}=6,D_{1}=15,M_{2}=(7+n)\ and\ D_{2}=9$

    ⇒$90=63+9n$

    ⇒$9n=90-63$

    ⇒$9n=27$

    ⇒$n=\frac{27}{9}$

    ∴ $n=3$

Therefore, The value of $n$ is $3$.