Question

The tuning circuit of a radio receiver has a resistance of
50 ???? , an inductor of 10 mH and a variable capacitor. A
1 MHz radio wave produces a potential difference of
0.1 mV. The values of the capacitor to produce resonance is
(Take π² = 10)
(a) 2.5 pF (b) 5.0 pF (c) 25 pF (d) 50 pF

Answer 1

Answer:

(Take π² = 10)

(a) 2.5 pF (b)

Explanation:

here is your answer.

hope it will help you.........!!

Answer 2

option a 2.5 pF is correct