Math, asked by samarvirk3485, 9 months ago

The turfing of rectangular field 85 paise per square metre is rupees 624.75 find the perimeter of the field if it side are in the ratio 5 ratio 3

Answers

Answered by sandeep10shaw
6

Answer:

Step-by-step explanation:

Turfing per m^2 = 0.85

Total cost of turfing = 624.75

As the sides are in the ratio 5:3

Let it be 5x and 3x respectively,

According to given condition,

0.85 * 5x * 3x = 624.75

x^2 = 49

x = 7,-7

Since the dimensions cannot be negative.

Therefore x= 7m

The dimensions are :

Length= 5x = (5*7) = 35m

Breadth= 3x=(3*7)= 21m

Hence perimeter = 2*(35+21)

= 2*56 = 112m

Answered by v07732vivasvat
0

Answer:

Length=2.295

Breadth =1.377

Step-by-step explanation:

Let 5:3 be the common multiples of x

Therefore we get 2 numbers 5x and 3x

Perimeter of rectangle =2(l+b)

=2(5x+3x)

=2(8x)

=16x

Now total cost = perimeter(cost of turfing 1square m)

Therefore

624.75=16x (85 paise)

624.75÷85=16x

7.35=16x

7.35÷16=x

0.459=x

Therefore 5x=5(0.459)

=2.295

And 3x=3(0.459)

=1.377

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