The two adjacent angles of a rectangle are 3a-b and 6b-a. Find its perimeter
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2 [(3a - b)+(6b-a)]
=2 (3a-b+6b-a)
=2 (2a+5b)
=4a+10b
=2 (3a-b+6b-a)
=2 (2a+5b)
=4a+10b
DhyeyKotecha:
Thanks!
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