Question

The two adjacent sides of a rectangle
are 2x°-5xy + 3z° and 4xy-x°-2°
find its perimeter
perimeter of a rectangle is 2(l+b)​

Answer 1

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Answer 2

Answer:

Let a and b be two adjacent sides of rectangle.

Then we know perimeter of rectangle will be 2(a+b).

Here two adjacent sides are 2x

2

−5xy+3z

2

and 4xy−x

2

−z

2

.

Thus perimeter = 2(a+b)=2(2x

2

−5xy+3z

2

+4xy−x

2

−z

2

)

=2(x

2

+2z

2

−xy)

=2x

2

+4z

2

−2xy