Question

The two adjacent sides of a rectangle are 3a - b and 6b - a. Find its perimeter.​

Answer 1

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ANSWER ⏬

✏️ Given :-

Adjacent sides of rectangle :-

➡ 3a -b

➡ 6b -a

Question :- perimeter ??

________

Perimeter of rectangle = 2( l+B)

________

Here l = 3a-b ; b = 6b -a

Perimeter = 2[ ( 3a-b + 6b -a ) ]

➡ 2 ( 2a +5b )

➡ 4a + 10b

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Hence the perimeter of given rectangle is 4a +10b

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Answer 2

Answer:

We know that

Perimeter of rectangle = 2(l+b)

= 2 (3a-b+6b-a)

= 2(2a+5b)

= 4a+10b