Question

the two adjacent sides of a rectangle are 3a-b and 6b-a. find its perimeter​

Answer 1

Step-by-step explanation:

perimeter of rectangle=2(length+width)

= 2(3a-b+6b-a)

=2(2a+5b)

=4a+10b

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Answer 2

Answer:

Given,

Two adjacent sides of reactangle are (3a-b),(6b-a).

=} let their length and breadth be (3a-b) & ( 6b-a).

We know that,

Perimeter of rectangle = 2 ( length + breadth )

=} perimeter = 2(3a-b+6b-a)

=} perimeter = 2(2a + 5b)

=} perimeter = 2(2a + 5b)

=} perimeter = 4a + 10b units.

Therefore, the perimeter of the given Rectangle is 4a + 10b units.