Question

the two adjacent sides of a rectangle are 3a - b and 6b - a. Find its perimeter

Answer 1

Perimeter of rectangle = 2(l+b)
Taking 3a-b =l and 6b-a=b
Perimeter= 2(3a-b+6b-a)
= 2(2a+5b)
= 4a+10b

Answer 2

Given sides of triangle : (3a-b) &

(6b-a)

therefore lets take length&breathe as 3a-b

as you know perimeter of rectangle:2(l+b)

so, 2(6b-a+3a-b) so, tarnsposing

I.e 2(3a-b+b-6b)

ans:4a+10b