the two adjacent sides of a rectangle are (3x + 2) cm, and (2y-1) cm. Fine the perimeter of the rectangle
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Given adjacent sides of a rectangle are 5x
2
−3y
2
and x
2
+2xy
we know that the perimeter of a rectangle with adjacent sides a and b is 2×(a+b)
Perimeter=2((5x
2
−3y
2
)+(x
2
+2xy))
=2(6x
2
−3y
2
+2xy)
=12x
2
−6y
2
+4xy
∴Perimeter=12x
2
−6y
2
+4xy
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