Question

the two adjacent sides of a rectangle are 3x square -2y square and x square+ 3xy. find its perimetre

Answer 1

Answer:

8x^2-4y^2+6xy

Step-by-step explanation:

Given adjacent sides

(3x^2-2y^2) and (x^2+3xy)

as they are adjacent sides so we can tell that (3x^2-2y^2) is length and (x^2+3xy) is breadth

Perimeter of a rectangle= 2(L+B)

by substituting values we get

perimeter= 2(3x^2-2y^2+x^2+3xy)

                = 2(3x^2+x^2-2y^2+3xy)

                = 2(4x^2-2y^2+3xy)

                = 8x^2-4y^2+6xy