Question

the two adjacent sides of a rectangle are 5xsquare -3ysquare and xsquare+2xy.find the perimeter​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given adjacent sides of a rectangle are 5x2−3y2 and x2+2xy

we know that the perimeter of a rectangle with adjacent sides a and b is 2×(a+b)

Perimeter=2((5x2−3y2)+(x2+2xy))

                =2(6x2−3y2+2xy)

                =12x2−6y2+4xy

∴Perimeter=12x2−6y2+4xy