Question

the two adjacent sides of a rectangle are 6a + 9b and 8a - 4 b find its perimeter​

Answer 1

let length= 6a+9b , breadth =8a-4b

perimeter of rectangle= 2(l+b)

= 2(6a+9b+8a-4b)

= 2(14a+5b)

=28a+10b

Answer 2

Answer:

28a+10b

Step-by-step explanation:

Let Length = 6a+9b , Breadth = 8a-4b

Perimeter of rectangle = 2(Length + Breadth)

= 2(6a+ab) + 8a-4b

= 2(14a+5b)

= 28a+10b

Therefore the perimeter of rectangle is 28a+10

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