the two adjacent sides of a rectangular plot are y-6x +3z+8 and x-2y-5z-8 find the perimeter of the plot
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Two adjacent sides are given.
Assume the first side or length be be y-6x+3z+8.
and second side or width be x-2y-5z-8.
Perimeter of the rectangle=2*(l+b)
=2*(y-6x+3z+8+x-2y-5z-8)
=2*(-y-5x-2z)
=-2y-10x-4z
The perimeter of the rectangle is -2y-10x-4z
Assume the first side or length be be y-6x+3z+8.
and second side or width be x-2y-5z-8.
Perimeter of the rectangle=2*(l+b)
=2*(y-6x+3z+8+x-2y-5z-8)
=2*(-y-5x-2z)
=-2y-10x-4z
The perimeter of the rectangle is -2y-10x-4z
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Answered by
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perimeter of rectangle =2*(l+b)
=2*[(y-6x+3z+8)+(x-2y-5z-8)]=2[y-6x+3z+8+x-2y-5z-8]=2[y-2y-6x+x+3z-5z+8-8]=2[-y-5x-2z]=-2y-10x-4z answer
=2*[(y-6x+3z+8)+(x-2y-5z-8)]=2[y-6x+3z+8+x-2y-5z-8]=2[y-2y-6x+x+3z-5z+8-8]=2[-y-5x-2z]=-2y-10x-4z answer
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