The two adjacent sides of rectangle are 5a²-3b² and a²+2ab Find the perimeter
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Answer:
So the perimeter will be like this
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Question:
The two adjacent sides of a rectangle are 5a²- 3b² and a²+ 2ab. Find the perimeter .
Solution:
ATQ, two adjacent sides are given by 5a²- 3b² & a²+ 2ab. Let them be the length and breadth of the rectangle respectively.
- Length (l) = 5a²- 3b²
- Breadth (b) = a² + 2ab
Let the rectangle be named PQRS.
We know that,
- Perimeter of a rectangle = 2 × (Length + Breadth
Using this formula we get,
→ Perimeter(PQRS) = 2(l + b)
→ Perimeter(PQRS) = 2(5a²- 3b² + a² + 2ab)
→ Perimeter(PQRS) = 2(5a² + a² - 3b² + 2ab)
→ Perimeter(PQRS) = 2(6a² - 3b² + 2ab)
→ Perimeter(PQRS) = 12a² - 6b² + 4ab
Final answer:
12a² - 6b² + 4ab
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