Question

The two adjacent sides of rectangle are 5a²-3b² and a²+2ab Find the perimeter

Answer 1

Answer:

So the perimeter will be like this

Hope it will help you

Answer 2

Question:

The two adjacent sides of a rectangle are 5a²- 3b² and a²+ 2ab. Find the perimeter .

Solution:

ATQ, two adjacent sides are given by 5a²- 3b² & a²+ 2ab. Let them be the length and breadth of the rectangle respectively.

• Length (l) = 5a²- 3b²
• Breadth (b) = a² + 2ab

Let the rectangle be named PQRS.

We know that,

• Perimeter of a rectangle = 2 × (Length + Breadth

Using this formula we get,

→ Perimeter(PQRS) = 2(l + b)

→ Perimeter(PQRS) = 2(5a²- 3b² + a² + 2ab)

→ Perimeter(PQRS) = 2(5a² + a² - 3b² + 2ab)

→ Perimeter(PQRS) = 2(6a² - 3b² + 2ab)

→ Perimeter(PQRS) = 12a² - 6b² + 4ab

Final answer:

12a² - 6b² + 4ab