Question

the two angles. of a quadrilateral are 36°and 72° the other two angle are in the ratio of 3:4 find the other two angles​

Answer 1

Answer:

108° and 144°

Explanation:

Given :---------------

Let is assume a quadrilateral ABCD and take angle A=36°

and angle B=72°.

We know that sum of all angles in a quadrilateral=360°.

Ratio of angle C and angle D=3:4

Let angle C be 3x and angle D be 4x.

Proof :------------------

Angle A+ Angle B+ Angle C+ Angle D = 360°

36°+72°+3x+4x = 360° (On substituting values from given)

108°+7x = 360°

7x = 360°-108°

7x = 252°

x = 252°/7

x = 36°

Now,

Angle C = 3x = 3(36°) = 108°

Angle D = 4x = 4(36°) = 144°

Therefore, the other two angles of the quadrilateral are 108° and 144°.

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Answer 2

Answer:

let the ratio be x

then, the angles are 36°, 72°,3x, 4x.

a/q

sum of the all angles of a quadrilateral is 360°

then,. 36°+ 72°+ 3x + 4x = 360°

108° + 7x = 360°

7x = 252°

x = 36°

now,

put the value of x in ratios

3x = 3 * 36

= 108°

4x= 4 * 36

= 144°

Hence, the two angles are 108° and 144°