The two base angles of a trapezium are 140 and 110. Find the other two angles.
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Answer:
Let a be 140° and b be 110°
To find : C and d
Proof:
We know that a+b+c+d = 360° (as the sum of all the angles in a quadrilateral is 360°)
140°+110°+c+d = 360°
250°+c+d= 360°
c+d = 110°
Let c=d=x
X+X=110°
2x= 110°
X = 55°
Therefore, c = d = 55°
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