Question

The two bones (femurs), each of cross sectional area 10 cm square support the upper part of a human body of mass 40 kg. Estimate the total pressure sustained by the both femurs. (given G = 10 M per second square)

Answer 1

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Formula to be used.
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$\bf \: = > force(f) = mass(m) \times acceleration(g)$
$\\ \\ \bf \: \: = > pressure(p) = force(f) \div area(a)$
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Given:-
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=> Acceleration or Gravity (g) =10 m/s²

=> Area of cross-section (a) = 10 cm ²

$= \frac{10}{100 \times 100} = 0.001 \: \: m ^{2}$

=> Mass (m) = 40 kg
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Now.
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$\bf \: = > force(f) = m \times g = 40 \times 10 = 400 \: \: newton \\ \\ \bf \: = > pressure(p) = f \div a = \frac{400}{0.001 } = 4 \times {10}^{5} \: pascal \\ \\ \bf \: = 4 \: \: bar. \:\: or \: \: 4\times {10}^{5 } Pa$

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Answer 2

Answer:

heya user kindly check ncert book first exampe of this chapter of class 11 , this ques is a ncert example

Explanation:

hope it helps