Question

the two bulbs of volume 5 litre and 20 litre containing an ideal gas at 9 atm and 6 atm respectively are connected what is the final pressure in two bulbs if the temperature remains constant

Answer 1

P1V1 + P2V2 = P(V1 + V2)
5*9 + 20*6 = P(25)
45 + 120 = 25P
165÷25= P
P = 6.6 atm

Answer 2

Answer : The final pressure in two bulbs is, 6.6 atm

Solution :

Formula used :

$P_1V_1+P_2V_2=P(V_1+V_2)$

where,

$P_1$ = pressure in 1st bulb = 9 atm

$P_2$ = pressure in 2nd bulb = 6 atm

$V_1$ = volume in 1st bulb = 5 L

$V_2$ = volume in 2nd bulb = 20 L

$P$ = total pressure after connecting the bulbs

Now put all the given values in the above formula, we get the final pressure in the two bulbs.

$(9atm)\times (5L)+(6atm)\times (20L)=P\times (5+20)L$

$P=6.6atm$

Therefore, the final pressure in two bulbs is, 6.6 atm