Physics, asked by Poulomee, 7 months ago



The two charges of +45 Coulomb and -75 Coulomb are at a distance of 3 meters from each other and the working force between them is 5 * 10 ^ 8 Newtons. What is the value of the active force if the value of the two charges is increased by 15 coulombs while keeping the distance unchanged?

Answers

Answered by Poulomee12
0

Answer:

Explanation:

q1=+45

q2=-75

f=5*10^8 n

r=3 m

k=f*r^2/q1q2

    =4*10^6/3

after increasing 15c

f=(60*60/3*3)*4*10^6/3

 =5.33*10^8 n *(approx)

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