Question

The two coins are tossed simultaneously 1000 times and we get two heads 210 times , 1 head 550 times and no head 240 times . Find the probability of occurrence of these events .

Answer 1

Let ,

E1 be the event of getting two heads .

E2 be the event of getting one head .

E3 be the event of getting no head .

1) P ( E1 ) = No. of heads

No. of trials

= 210

1000

= 0.21

2) P ( E2 ) = No. of heads

No. of trials

= 550

1000

= 0.55

3) P ( E3 ) = No. of heads

No. of trials

= 240

1000

= 0.24

P ( E1 ) +P ( E2 ) + P ( E3 ) = 0.21 + 0.55 + 0.24

= 1

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