Question

the two consecutive integers between which the fraction 5/7 lies are​

Answer 1

Step-by-step explanation:

Let the first consecutive integer be x,

then Definitely, the other would be equal to (x+1),

Now, how do we find the mean number of two numbers?

We do this by this formula:-

1/2* (a+b); where a and b are the main numbers.

So,

$\frac{1}{2} (x + y) = \frac{5}{7 } \\ then \: (x + y) = \frac{10}{7} \\ (x + x + 1) = \frac{10}{7} \\ (2x + 1 ) = \frac{10}{7} \\ 2x = \frac{10}{7} - 1 \\ 2x = \frac{3}{7} \\ x = \frac{3}{14}$

and the other value is taken by adding 1 to it.

so, other value = 1+3/7= 10/7.

So, THE TWO VALUES ARE 3/7 AND 10/7.