The two consecutive multiples of 3 whose sum is 51 are
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answer - 24 and 27.
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let one no be=x
let another be =x+3
∴x+x+3=51(given sum=51)
2x=51-3
2x=48
x=48/2=24
∴one no=24
another no=24+3=27
let another be =x+3
∴x+x+3=51(given sum=51)
2x=51-3
2x=48
x=48/2=24
∴one no=24
another no=24+3=27
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