Question

The two consecutive odd integers, sum of whose square is 290 are Select one:

a. 10 & 11

b. 11 & 12

c. 11 & 13

d. 12 & 13

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Answer 1

Answer:

11 and 13

Step-by-step explanation:

Let the numbers be x and x + 2

==: x² + (x + 2)² = 290

==: x² + x² + 4 + 4x = 290

==: 2x² + 4x + 4 = 290

==: 2x² + 4x - 286 = 0

==: x² + 2x - 143 = 0

x = 11

x + 2 = 13

Option (c) is correct

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Answer 2

Answer:

C option

Step-by-step explanation:

Let the odd integer be x.

$=> x^{2} + (x+2)^{2} = 290$

=> $2x^{2} + 4x + 4 = 290$

=> 2x^{2} + 4x - 286 = 0

=> x = 11 or 13

Alternatively, you can also check by squaring 11 and 13, add them up and you will get 290.

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