the two consecutive positive even integers sum of the squares is 340 are
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Hie
the two numbers are 12 and 14.
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the two numbers are 12 and 14.
Steps in the pic.
hope it will help you.
Brainlist it if it helps you.
follow me for help
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Answered by
3
Hey
Here is your answer,
Let the two consecutive even numbers are x and x+2.
Given that ,
Sum of their squares is 340.
(x)^2 + (x+2)^2 = 340
X^2 + x^2 + 4 + 4x = 340
2x^2 + 4x = 336
2x^2 + 4x - 336 =0
Divide the equation by 2,
X^2 + 2x - 166 =0
X^2 + 14x - 12x - 166=0
X(x+14) - 12(x +14)=0
(x + 14)(x - 12) = 0
x = -14 or 12
The numbers are 12 and 14.
Hope it helps you!
Here is your answer,
Let the two consecutive even numbers are x and x+2.
Given that ,
Sum of their squares is 340.
(x)^2 + (x+2)^2 = 340
X^2 + x^2 + 4 + 4x = 340
2x^2 + 4x = 336
2x^2 + 4x - 336 =0
Divide the equation by 2,
X^2 + 2x - 166 =0
X^2 + 14x - 12x - 166=0
X(x+14) - 12(x +14)=0
(x + 14)(x - 12) = 0
x = -14 or 12
The numbers are 12 and 14.
Hope it helps you!
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